Integrand size = 21, antiderivative size = 163 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {5 \left (8 a^2-b^2\right ) \text {arctanh}(\sin (c+d x))}{128 d}+\frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {5 \left (8 a^2-b^2\right ) \sec (c+d x) \tan (c+d x)}{128 d}+\frac {5 \left (8 a^2-b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{192 d}+\frac {\left (8 a^2-b^2\right ) \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d} \]
[Out]
Time = 0.17 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3589, 3567, 3853, 3855} \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {5 \left (8 a^2-b^2\right ) \text {arctanh}(\sin (c+d x))}{128 d}+\frac {\left (8 a^2-b^2\right ) \tan (c+d x) \sec ^5(c+d x)}{48 d}+\frac {5 \left (8 a^2-b^2\right ) \tan (c+d x) \sec ^3(c+d x)}{192 d}+\frac {5 \left (8 a^2-b^2\right ) \tan (c+d x) \sec (c+d x)}{128 d}+\frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d} \]
[In]
[Out]
Rule 3567
Rule 3589
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d}+\frac {1}{8} \int \sec ^7(c+d x) \left (8 a^2-b^2+9 a b \tan (c+d x)\right ) \, dx \\ & = \frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d}+\frac {1}{8} \left (8 a^2-b^2\right ) \int \sec ^7(c+d x) \, dx \\ & = \frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {\left (8 a^2-b^2\right ) \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d}+\frac {1}{48} \left (5 \left (8 a^2-b^2\right )\right ) \int \sec ^5(c+d x) \, dx \\ & = \frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {5 \left (8 a^2-b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{192 d}+\frac {\left (8 a^2-b^2\right ) \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d}+\frac {1}{64} \left (5 \left (8 a^2-b^2\right )\right ) \int \sec ^3(c+d x) \, dx \\ & = \frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {5 \left (8 a^2-b^2\right ) \sec (c+d x) \tan (c+d x)}{128 d}+\frac {5 \left (8 a^2-b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{192 d}+\frac {\left (8 a^2-b^2\right ) \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d}+\frac {1}{128} \left (5 \left (8 a^2-b^2\right )\right ) \int \sec (c+d x) \, dx \\ & = \frac {5 \left (8 a^2-b^2\right ) \text {arctanh}(\sin (c+d x))}{128 d}+\frac {9 a b \sec ^7(c+d x)}{56 d}+\frac {5 \left (8 a^2-b^2\right ) \sec (c+d x) \tan (c+d x)}{128 d}+\frac {5 \left (8 a^2-b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{192 d}+\frac {\left (8 a^2-b^2\right ) \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b \sec ^7(c+d x) (a+b \tan (c+d x))}{8 d} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 216, normalized size of antiderivative = 1.33 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {5 a^2 \text {arctanh}(\sin (c+d x))}{16 d}-\frac {5 b^2 \text {arctanh}(\sin (c+d x))}{128 d}+\frac {2 a b \sec ^7(c+d x)}{7 d}+\frac {5 a^2 \sec (c+d x) \tan (c+d x)}{16 d}-\frac {5 b^2 \sec (c+d x) \tan (c+d x)}{128 d}+\frac {5 a^2 \sec ^3(c+d x) \tan (c+d x)}{24 d}-\frac {5 b^2 \sec ^3(c+d x) \tan (c+d x)}{192 d}+\frac {a^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}-\frac {b^2 \sec ^5(c+d x) \tan (c+d x)}{48 d}+\frac {b^2 \sec ^7(c+d x) \tan (c+d x)}{8 d} \]
[In]
[Out]
Time = 67.51 (sec) , antiderivative size = 177, normalized size of antiderivative = 1.09
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\left (-\frac {\left (\sec ^{5}\left (d x +c \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (d x +c \right )\right )}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )+\frac {2 a b}{7 \cos \left (d x +c \right )^{7}}+b^{2} \left (\frac {\sin ^{3}\left (d x +c \right )}{8 \cos \left (d x +c \right )^{8}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{48 \cos \left (d x +c \right )^{6}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{64 \cos \left (d x +c \right )^{4}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{128 \cos \left (d x +c \right )^{2}}+\frac {5 \sin \left (d x +c \right )}{128}-\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{128}\right )}{d}\) | \(177\) |
default | \(\frac {a^{2} \left (-\left (-\frac {\left (\sec ^{5}\left (d x +c \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (d x +c \right )\right )}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )+\frac {2 a b}{7 \cos \left (d x +c \right )^{7}}+b^{2} \left (\frac {\sin ^{3}\left (d x +c \right )}{8 \cos \left (d x +c \right )^{8}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{48 \cos \left (d x +c \right )^{6}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{64 \cos \left (d x +c \right )^{4}}+\frac {5 \left (\sin ^{3}\left (d x +c \right )\right )}{128 \cos \left (d x +c \right )^{2}}+\frac {5 \sin \left (d x +c \right )}{128}-\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{128}\right )}{d}\) | \(177\) |
risch | \(-\frac {i {\mathrm e}^{i \left (d x +c \right )} \left (840 a^{2} {\mathrm e}^{14 i \left (d x +c \right )}-105 b^{2} {\mathrm e}^{14 i \left (d x +c \right )}+6440 a^{2} {\mathrm e}^{12 i \left (d x +c \right )}-805 b^{2} {\mathrm e}^{12 i \left (d x +c \right )}+21448 a^{2} {\mathrm e}^{10 i \left (d x +c \right )}-2681 b^{2} {\mathrm e}^{10 i \left (d x +c \right )}+15848 a^{2} {\mathrm e}^{8 i \left (d x +c \right )}+19523 b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+49152 i a b \,{\mathrm e}^{8 i \left (d x +c \right )}-15848 a^{2} {\mathrm e}^{6 i \left (d x +c \right )}-19523 b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+49152 i a b \,{\mathrm e}^{6 i \left (d x +c \right )}-21448 a^{2} {\mathrm e}^{4 i \left (d x +c \right )}+2681 b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-6440 a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+805 b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-840 a^{2}+105 b^{2}\right )}{1344 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{8}}-\frac {5 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{16 d}+\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) b^{2}}{128 d}+\frac {5 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{16 d}-\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) b^{2}}{128 d}\) | \(383\) |
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.00 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {105 \, {\left (8 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{8} \log \left (\sin \left (d x + c\right ) + 1\right ) - 105 \, {\left (8 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{8} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 1536 \, a b \cos \left (d x + c\right ) + 14 \, {\left (15 \, {\left (8 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{6} + 10 \, {\left (8 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{4} + 8 \, {\left (8 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + 48 \, b^{2}\right )} \sin \left (d x + c\right )}{5376 \, d \cos \left (d x + c\right )^{8}} \]
[In]
[Out]
\[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\int \left (a + b \tan {\left (c + d x \right )}\right )^{2} \sec ^{7}{\left (c + d x \right )}\, dx \]
[In]
[Out]
none
Time = 0.32 (sec) , antiderivative size = 220, normalized size of antiderivative = 1.35 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {7 \, b^{2} {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{7} - 55 \, \sin \left (d x + c\right )^{5} + 73 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{8} - 4 \, \sin \left (d x + c\right )^{6} + 6 \, \sin \left (d x + c\right )^{4} - 4 \, \sin \left (d x + c\right )^{2} + 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 56 \, a^{2} {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{5} - 40 \, \sin \left (d x + c\right )^{3} + 33 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + \frac {1536 \, a b}{\cos \left (d x + c\right )^{7}}}{5376 \, d} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 437 vs. \(2 (151) = 302\).
Time = 0.59 (sec) , antiderivative size = 437, normalized size of antiderivative = 2.68 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {105 \, {\left (8 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 105 \, {\left (8 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (1848 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{15} + 105 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{15} - 5376 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{14} - 3416 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} + 2779 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} + 5376 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{12} + 6328 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 6265 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 26880 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} - 4760 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 12355 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 26880 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 4760 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 12355 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 16128 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 6328 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6265 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 16128 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 3416 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2779 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 768 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1848 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 105 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 768 \, a b\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{8}}}{2688 \, d} \]
[In]
[Out]
Time = 8.17 (sec) , antiderivative size = 432, normalized size of antiderivative = 2.65 \[ \int \sec ^7(c+d x) (a+b \tan (c+d x))^2 \, dx=\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (\frac {5\,a^2}{8}-\frac {5\,b^2}{64}\right )}{d}+\frac {\left (\frac {11\,a^2}{8}+\frac {5\,b^2}{64}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}-4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+\left (\frac {397\,b^2}{192}-\frac {61\,a^2}{24}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}+4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+\left (\frac {113\,a^2}{24}+\frac {895\,b^2}{192}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}-20\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+\left (\frac {1765\,b^2}{192}-\frac {85\,a^2}{24}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+20\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+\left (\frac {1765\,b^2}{192}-\frac {85\,a^2}{24}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7-12\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+\left (\frac {113\,a^2}{24}+\frac {895\,b^2}{192}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+12\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+\left (\frac {397\,b^2}{192}-\frac {61\,a^2}{24}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3-\frac {4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{7}+\left (\frac {11\,a^2}{8}+\frac {5\,b^2}{64}\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+\frac {4\,a\,b}{7}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}-8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+28\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-56\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+70\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-56\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+28\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
[In]
[Out]